广义二项式定理

1(1+x)n=∑k=0∞(n+k−1k−1)xk\frac{1}{(1+x)^n}=\sum_{k=0}^{\infty}\begin{pmatrix}n+k-1\\k-1\end{pmatrix}x^k


各种变换

∑i=1∞xi=11−x\sum_{i=1}^{\infty}x_i=\frac{1}{1-x}

ex=∑i=0∞xii!e^x=\sum_{i=0}^{\infty}\frac{x^i}{i!}

e−x=1−x1+x22!−x33!+…e^{-x}=1-\frac{x}{1}+\frac{x^2}{2!}-\frac{x^3}{3!}+\dots

ex+e−x2=1+x22!+x44!+626!+…\frac{e^x+e^{-x}}{2}=1+\frac{x^2}{2!}+\frac{x^4}{4!}+\frac{6^2}{6!}+\dots

ex+e−x2=1+x33!+x55!+x77!+…\frac{e^x+e^{-x}}{2}=1+\frac{x^3}{3!}+\frac{x^5}{5!}+\frac{x^7}{7!}+\dots

ekx=1+x1+k2x22!+k3x33!+…e^{kx}=1+\frac{x}{1}+\frac{k^2x^2}{2!}+\frac{k^3x^3}{3!}+\dots